Madhyamik Question Paper Solution of Year 2023 Question No: 8(ii)
\(\frac{a^2}{b+c} = \frac{b^2}{c+a} = \frac{c^2}{a+b} = 1\) হলে দেখাও যে \(\frac{1}{1+ a} + \frac{1}{1+b} + \frac{1}{1+c} = 1\)

\(\frac{a^2}{b+c} = \frac{b^2}{c+a} = \frac{c^2}{a+b} = 1\) হলে দেখাও যে \(\frac{1}{1+ a} + \frac{1}{1+b} + \frac{1}{1+c} = 1\)