Class 11 Book Solution from Miscellaneous in General solutions of Equations of Trigonometric Functions Question No: 203
\(\frac{x^2}{169}+ \frac{y^2}{25} = 1\) এবং \(\frac{x^2}{a^2}+ \frac{y^2}{b^2} = 1 [a^2>b^2]\) এই উপবৃত্ত দুটির উৎকেন্দ্রতা একই হলে \(a \over b\) এই অনুপাতটি নির্ণয় করো ।
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